WELL ANONS? CAN YOU SOLVE WHAT A 74 YEARS OLD MAN IS BEING MADE FUN FOR SOLVING?
> if you fail post here and admit to your capitulation, be a white man and own up to your shortcomings
WELL ANONS? CAN YOU SOLVE WHAT A 74 YEARS OLD MAN IS BEING MADE FUN FOR SOLVING?
> if you fail post here and admit to your capitulation, be a white man and own up to your shortcomings
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You want me to solve fermat's last theorem? That has already been proven?
Proven...that is, to be false
Doesn’t the exponent have to be greater than 2?
Wait nevermind I’m retarded.
Yes, it's easy. There's none.
Makise could have worn either shorts or long pants but somehow she chose something in between. You can't explain that.
If:
>A=3
>B=4
>C=5
Is given for the first problem,
Then
>A=√3
>B=√4
>C=√5
Is still too hard for niggers to grasp
This.
Wait no, they have to be natural numbers. I guess I'm a nigger.
It is greater than 2 lol
I'm drunk and didn't come here for math. Fuck you
/thread
MATH IS MADE FOR THE BBC
>Natural
Back to smoking weed toothpaste
"Fermat's Last Theorem"
that no solution exists was conjectured by Pierre de Fermat around 1637
proven in 1993 Andrew Wiles
this
It's not a Fermat's Last Theorem.
Christina's fashion choices are never put into question whatsoever in the VN and it irritates me somehow.
Like who tf wear both? Why?
436
from what i recall, isnt getting two roots out from under a large encompassing root much more difficult. ill tel you whats difficult, wording this.
>In number theory, Fermat's Last Theorem (sometimes called Fermat's conjecture, especially in older texts) states that no three positive integers a, b, and c satisfy the equation a^n + b^n = c^n for any integer value of n greater than 2.
in op pic n=4 therefor no natural solutions exist which are not zero or one
How so?
Unfortunately, "natural number" is retardspeak for integer.
The answer is...
Green.
>integer
Yeah dude, I like going to the store and getting -3 packs of cereals
What is the name of that tranny anyway?
1
1
And 1
Because that theorem is specifically about 3rd powers, not 4th.
From what I recall it's *any* above 2
natural numbers are non-negative integers, nigger
When people talk about Fermat's Last Theorem they mean the one that was not proven until recently. 4th power and everything above was proven ages ago.
thank you russian math historian
The theorem is true, that is to say *no* such integers exist.
Sure 1+1=1
a = 477788107040579609,
b = 620046030249257067,
c = 668673151671010816
What is floating point error and rounding.
Probably everyone just searched the formula. Kek sage thread. Useless
I see what you mean now, thank you for answers