It's declaring an array with the name main and a size of -1u. -1u is unsigned -1, or 4294967295. It's implicitly typed int, which means the array is 16 GB large on most architectures. The first element is set to 1, all the others are set to 0. All of that is dumped in the binary, so the file will be 16 GB+ and the compiler won't be very responsive. There's no main function, but because the symbol is called "main" the linker will accept it. The executable will be created but won't work.
ITT: We critique each others fizzbuzzes
Bentley Ward
Isaac Powell
I'd rather take a bloated program than a slow program.
Mason Cook
So I was in the right staying sceptical of actually attempting to compile it.
Nicholas Hall
seq 100|sed 5~5cBuzz|sed 3~3s/[^B]*/Fizz/
Anthony Thompson
...
Andrew King
GNU isn't perfect but it sure is better than traditional inefficient arbitrarily-limited Unix.
Grayson Sanchez
while($counter++,$num++ -lt 100){ $mod3 = $num % 3 $mod5 = $num % 5 if($mod3 -eq 0 -and $mod5 -eq 0){ Write-Output FizzBuzz }elseif($mod5 -eq 0){ Write-Output Buzz }elseif($mod3 -eq 0){ Write-Output Fizz }else{ Write-Output $num }}
Nathan White
sauce? are there n00dez?
William Thomas
Care to explain this bit? It really confuses me.
Nolan Carter
The suffix "u" makes the compiler read the integer as an unsigned integer. Because it is almost guaranteed that the computer uses two-complement to represent integers, signed -1 is equivalent to the maximum permitted unsigned integer, i.e. 1111 1111 1111 1111...
So, he's creating an array of UINT_MAX which contains the number 1 everywhere.